X^2+100x-14400=0

Solution for X^2+100x-14400=0 equation:

X^2+100X-14400=0

a = 1; b = 100; c = -14400;
Δ = b2-4ac
Δ = 1002-4·1·(-14400)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67600}=260$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-260}{2*1}=\frac{-360}{2}
=-180
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+260}{2*1}=\frac{160}{2}
=80
$